How do you solve #(x-1)/3 -( x-1) /2 = 6#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Harshit Tiwari · Mahek ☮ Mar 20, 2018 #x=-35# Explanation: #(x-1)/3-(x-1)/2=6# #{2(x-1)-[3(x-1)]}/6=6# #2x-2-[3x-3]=36# #2x-2-3x+3=36# #1-x=36# #x=-35# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1594 views around the world You can reuse this answer Creative Commons License