Question

How do you solve the equation `3(x^2+2)=18`?

Answer 1

`2`

Explanation:

`x^2 +2=18/3`

`x^2 +2=6`

`x^2 =6-2`

`x^2=4`

`x=sqrt(4)`

`x=2`

Answer 2

`x = +-2`

Explanation:

Given   `3(x^2+2)=18`    Solve for `x`

1) Divide both sides by `3`
After you divide, you will get this:
`x^2 + 2 = 6`

2) Subtract `2` from both sides to isolate the `x^2` term
`x^2 = 4`

3) Find the square roots of both sides
`x = +-2`

       . . . . . . . . Check . . . . . . .

Using the original equation, sub in either `+2` or `-2` in the place of `x`. The equation should still equal `18`

`3(x^2+2)=18`

1) Sub in `-2`

`3((-2)^2+2)` should still equal `18`

2)Square the `-2`
`3 (4+2)` should still equal `18`

3) Add inside the parentheses
`3 (6)` should still equal `18`

4) Clear the parentheses by distributing the `3`
`18  "does equal"  18`

`Check`