How do you solve #\frac{7x}{x-5}=\frac{x+3}{x}#?

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Answer 1 · 2018-03-20T08:33:33

I personally believe you can't

multiply by the denominators to the opposite sides to make everything on one level:

#x(7x)=x-5(x+3)#

then multiply out the brackets@

#7x^2=x^2-2x-15#

then bring everything over on one side:

#6x^2+2x+15=0#

and then you can't factorise...