How do you find all the real and complex roots of x^3 + 4x^2 + 3x = 0x3+4x2+3x=0?

1 Answer
Mar 20, 2018

x^3+4x^2+4x=0x3+4x2+4x=0
x(x^2+4x+3)=0x(x2+4x+3)=0
implies x=0 and x^2 + 4x+3=0x2+4x+3=0
thus we got one root and the other two roots are obtained by solving x^2 + 4x+3=0x2+4x+3=0
(x+1)(x+3)=0(x+1)(x+3)=0
implies x=-1,x=-3
hence the roots are x=0,-1,-3