How do you solve the system of equations y=5-2x and 3x-2y=4 by substitution?

1 Answer
Mar 20, 2018

x=2 and y=1.

Explanation:

Since you know that y=5-2x, you substitute it into 3x-2y=4 to get 3x-2(5-2x)=4. Solving for x, you get 3x-10+4x=4, so 7x-10=4, and finally 7x=14, so x=2 Substituting x=2 into y=5-2x gives us y=5-2*2=5-4=1.