How do you factor #3v ^ { 2} + 12v - 63#?
3 Answers
Explanation:
Given
First factor out the obvious constant
Then look for two numbers whose product is
With a bit of playing around you should come up with
enabling the continuation of the factoring:
Explanation:
Given:
#3x^2+12v-63#
First note that all of the coefficients are divisible by
#3v^2+12v-64 = 3(v^2-4v-21)#
To factor the remaining quadratic, we can find a pair of factors of
Hence we find:
#v^2-4v-21 = (v-7)(v+3)#
So:
#3x^2+12v-63 = 3(v-7)(v+3)#
Explanation:
First you take
Then factorise the middle:
so
and
so the final answer would be