29²+35²+33²+31²-34²-32²-30²-28²=?

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Answer 1 · 2018-03-21T06:05:59

$29^{2} + 35^{2} + 33^{2} + 31^{2} - 34^{2} - 32^{2} - 30^{2} - 28^{2} = 252$ $29^2+35^2+33^2+31^2-34^2-32^2-30^2-28^2 =252$

In order to solve this question, we must first consider the value of each of the square numbers. This is done in the following way:
$(29 \cdot 29) + (35 \cdot 35) + (33 \cdot 33) + (31 \cdot 31) - (34 \cdot 34) - (32 \cdot 32) - (30 \cdot 30) - (28 \cdot 28)$ $(29*29)+(35*35)+(33*33)+(31*31)-(34*34)-(32*32)-(30*30)-(28*28)$
We then carry out the multiplication to solve each for each multiplication. This is done in the following way:
$(841) + (1225) + (1089) + (961) - (1156) - (1024) - (900) - (784)$ $(841)+(1225)+(1089)+(961)-(1156)-(1024)-(900)-(784)$
We then carry out the addition and subtraction:
$(841) + (1225) + (1089) + (961) - (1156) - (1024) - (900) - (784) = 252$ $(841)+(1225)+(1089)+(961)-(1156)-(1024)-(900)-(784)=252$