How do you solve the inequality $- 4 < 2 + x < 1$ $-4 < 2 + x <1$ ?

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How do you solve the inequality $- 4 < 2 + x < 1$ $-4 < 2 + x <1$ ?

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Answer 1 · 2018-03-21T11:02:13

$x \in (- 6, - 1)$ $x in (-6,-1)$

Explanation:

Add $- 2$ $-2$ to each term

$- 4 - 2 < 2 - 2 + x < 1 - 2$ $-4-2 < 2-2+x < 1-2$ or

$- 6 < x < - 1$ $-6 < x < -1$ so

$x \in (- 6, - 1)$ $x in (-6,-1)$

Answer 2 · 2018-03-21T11:05:44

$- 6 < x < - 1$ $-6< x < -1$

Explanation:

$Isolate x in the middle interval by subtracting 2 from all 3$ $"Isolate x in the middle interval by subtracting 2 from all 3"$
$intervals$ $"intervals"$

$-4color(red)(-2)< cancel(2)cancel(color(red)(-2))+x<1color(red)(-2)$

$rArr-6 < x < -1$

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How do you solve the inequality $- 4 < 2 + x < 1$ $-4 < 2 + x <1$ ?

2 Answers

Explanation:

Explanation:

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How do you solve the inequality -4 < 2 + x <1−4<2+x<1-4 < 2 + x <1?

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How do you solve the inequality $- 4 < 2 + x < 1$ $-4 < 2 + x <1$ ?