How do you find the slope of a tangent line to the graph of the function $F (t) = 3 - (\frac{8}{3} t)$ $F(t)= 3- (8/3t)$ at point: (2/4, -7/3)?

Question

1773 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-21T14:02:07

There is no such line.

The point $(\frac{2}{4}, - \frac{7}{3})$ $(2/4,-7/3)$ is not on the graph of that function.

But at any point $(\frac{a}{b})$ $(a/b)$ that is on the graph, the slope of the tangent line is the same as the slope of the line.

So it is $- \frac{8}{3}$ $-8/3$

How do you find the slope of a tangent line to the graph of the function F(t)=3−(83t)F(t)= 3- (8/3t) at point: (2/4, -7/3)?