How do you evaluate ${log}_{125} (\frac{1}{5})$ $log_125 (1/5)$ ?

Question

3784 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-21T16:30:41

It is

${log}_{125} (\frac{1}{5}) = - {log}_{125} 5 = - \frac{log 5}{{log 5}^{3}} = - \frac{1}{3}$ $log_125(1/5)=-log_125 5=-(log5)/(log5^3)=-1/3$

How do you evaluate log125(15)log_125 (1/5)?