How do i find z?

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How do i find z?

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Answer 1 · 2018-03-21T21:46:23

Side z is $3 \sqrt{3}$ $3sqrt(3)$ .

Explanation:

Since this is a right angle triangle, we can use the primary trigonometric ratios.
$sin (x)$ $sin(x)$ =opposite/hypotenuse
$sin (60) = \frac{z}{6}$ $sin(60)=z/6$
$z = 6 \cdot sin (60)$ $z=6*sin(60)$
$z = 6 \cdot \frac{\sqrt{3}}{2}$ $z=6*(sqrt(3))/2$
$z = 3 \sqrt{3}$ $z=3sqrt(3)$

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How do i find z?

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