$f = {(x - 2014)}^{2014} + 3 x + 12$ $f=(x-2014)^2014+3x+12$ The remainder for $f : (x - 1)$ $f:(x-1)$ is?

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Answer 1 · 2018-03-22T09:54:39

$r = 2013^{2014} + 15$ $r = 2013^2014+15$

$f (x) = (x - 1) q (x) + r$ $f(x) = (x-1)q(x)+ r$ then

$f (1) = r$ $f(1) = r$ or

$r = 2013^{2014} + 15$ $r = 2013^2014+15$

f=(x−2014)2014+3x+12f=(x-2014)^2014+3x+12 The remainder for f:(x−1)f:(x-1) is?