How do you solve #\frac { 9} { 8} x - 1\leq 5x - \frac { 7} { 4}#?

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Answer 1 · 2018-03-22T11:56:45

#x>=6/31#

As always do some cleanup:

#9/8x-5x <= -7/4+ 1#

#-31/8x<=-3/4#

Now we multiply by #-8#. Therefore the #<=# has to be changed to #>=#, resulting in

#31x>=6#.

Division by 31 solves the problem:

#x>=6/31#