How do you solve #p( - 5- p ) = 6#?
2 Answers
Mar 22, 2018
Explanation:
#"distribute and rearrange into "color(blue)"standard form"#
#rArr-5p-p^2=6#
#rArrp^2+5p+6=0larrcolor(blue)"in standard form"#
#"the factors of + 6 which sum to + 5 are + 3 and + 2"#
#rArr(p+3)(p+2)=0#
#"equate each factor to zero and solve for p"#
#p+3=0rArrp=-3#
#p+2=0rArrp=-2#
Mar 22, 2018
Explanation:
Using FOIL method :
Factorization (you can also use quadratic formula and completing square):