How do you solve $12 - x = 8 x - 1 - 9 x$ $12- x = 8x - 1- 9x$ ?

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Answer 1 · 2018-03-22T16:28:28

No solution

First push all the variables to one side. We get,

$9 x - 8 x - x$ $9x-8x-x$ = $- 12 - 1$ $-12-1$

we get,

$0$ $0$ = $- 13$ $-13$

This however is not possible. This means that the equation has no solution

Answer 2 · 2018-03-22T16:37:55

There are no solutions

$12 - x = 8 x - 1 - 9 x$ $12-x=8x-1-9x$

$12 - x = - x - 1$ $12-x = -x - 1$

Add $x$ $x$ on both sides

$12 - x + x = - x - 1 + x$ $12 - x + x = -x - 1 + x$

$12 = - 1$ $12 = -1$

Then subtract $12$ $12$ from both sides

$12 - 12 = - 1 - 12$ $12 - 12 = -1 -12$

$0 = 13$ $0=13$

Thus,

There are no solution!

How do you solve 12−x=8x−1−9x12- x = 8x - 1- 9x?