How do you solve $7x ^ { 2} - 9= 0$ ?

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Answer 1 · 2018-03-23T00:27:21

Read below.

We have:

$7x^2-9=0$ Add $9$ on both sides.

$7x^2=9$ Divide both sides by 7.

$x^2=9/7$ Apply square root on both sides.

$x=+-sqrt(9/7)$ That is our answer!

Alternatively, we can rewrite this as $x=+-sqrt(9)/sqrt(7)$ , which is equal to

$x=+-3/sqrt7$

If your teacher is picky, then you could even do this:

$3/sqrt7*sqrt7/sqrt7=>+-(3sqrt7)/7$

How do you solve 7x ^ { 2} - 9= 07x ^ { 2} - 9= 0?