Question

What is the volume occupied by 11.0 g of propane gas, C3H8, at STP? Question 35 options: 89.6 L 0.250 L 21.6 L 5.59 L 4.00 L

Answer 1

5.59L

Explanation:

As the conditions are STP,
we can apply mole concept.

We know,
Molar mass of `C_3` `H_8` =12(3)+8=44g
& Volume of every gas at STP is 22.4L.

So at STP,
44g of gas has 22.4L volume,
11g will have x L volume.

`x=(22.4*11)/44`
`=5.6L`

i.e `5.59 L`