How do you multiply #(2+x)^3#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer jk.13 Mar 23, 2018 #x^3+6x^2+12x+8# Explanation: We know that #(a+b)^3=a^3+3a^2b+3ab^2+b^3# In this case, #a=2# and #b=x# #2^3+3(2^2)(x)+3(2)(x^2)+x^3# #8+12x+6x^2+x^3# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1486 views around the world You can reuse this answer Creative Commons License