Write an equation in slope-intercept form for the line that passes through (-1, 4) and is perpendicular to the graph of the equation: y=3x+5 ?

Question

Write an equation in slope-intercept form for the line that passes through (-1, 4) and is perpendicular to the graph of the equation: y=3x+5 ?

1 Answer

Impact of this question

2705 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-24T00:46:23

$y = (- \frac{1}{3}) x - (\frac{1}{3}) + 4$ $y=(-1/3)x-(1/3)+4$

Explanation:

Provided that the line passes through $(- 1, 4)$ $(-1,4)$ and is perpendicular to line $y = 3 x + 5$ $y=3x+5$
We know
The product of gradients of two mutually perpendicular lines is $- 1$ $-1$
So
Let $m_{1} = 3$ $m_1 = 3$
We have to find $m_{2}$ $m_2$
So $m_{1} \times m_{2} = - 1$ $m_1 ×m_2 =-1$
$or, 3 \times m_{2} = - 1$ $or, 3×m_2 =-1$
Hence $m_{2} = - \frac{1}{3}$ $m_2 = -1/3$
Choose $m = - \frac{1}{3}$ $m=-1/3$
By point slope forme
$(y - y_{1}) = m (x - x_{1})$ $(y-y_1)=m (x-x_1)$
$or, (y - 4) = (- \frac{1}{3}) (x - (- 1)$ $or, (y-4)=(-1/3)(x-(-1)$
$or, (y - 4) = (- \frac{1}{3}) x - (\frac{1}{3})$ $or, (y-4)=(-1/3)x-(1/3)$
$or, y = (- \frac{1}{3}) x - (\frac{1}{3}) + 4$ $or, y=(-1/3)x-(1/3)+4$ is the required equation.

Science

Math

Humanities

... and beyond

Write an equation in slope-intercept form for the line that passes through (-1, 4) and is perpendicular to the graph of the equation: y=3x+5 ?

1 Answer

Explanation:

Related questions

Impact of this question