#53 + 4 xx c = 21#. What is #c#?

3 Answers
Mar 24, 2018

#c = -8#

Explanation:

#53 + 4 xx c = 21# is the same as #53 + 4c = 21.#

(You cannot add 53 and 4 because of the order of operations)

Subtract #53# from each side:

#cancel53+4c-cancel53=21-53#

#4c= -32#

Divide each side by #4# to get

#(4c)/4=-32/4#

#c = -8#

Mar 24, 2018

#c=-8#

Explanation:

#53+4*c = 21#

#4c=21-53#

#4c = -32#

#c= -32/4#

#c = -8#

#c= -8#

:)

Mar 24, 2018

#c =-8#

Explanation:

Notice that there are two terms on the left side.

#color(blue)(53) + color(red)(4xxc) = 21#

Simplifying gives:#" "color(blue)(53) + color(red)(4c) = 21#
(Remember to multiply first)

#color(blue)(53) and color(red)(4c)# are unlike terms and cannot be added.

To solve the equation:
isolate # color(red)(4c)# by subtracting #53# on both sides.

#53+4c-53 = 21-53#

#4c = -32#

#c =-8#