What is #(1 3/4+2 3/8) + 5 7/8#?

1 Answer
Mar 24, 2018

#10#

Explanation:

First convert them all into improper fractions

#(1 3/4 + 2 3/8) + 5 7/8#

#(7/4 + 19/8) + 47/8#

Write #7/4# as #14/8#

Now, since they all have the same denominator, we can add the numerators

#=(14+19+47)/8#

#=80/8#

#=10#