How do you solve the system #y=4x-5# and #x=2# by substitution?

2 Answers
Mar 24, 2018

#x = 2# and #y = 3#

Explanation:

The value of #x# is given in the second equation, so all you have to do is substitute that value for #x# in the first equation and then solve for #y#:
#y = 4x - 5#
#y = 4(2) - 5#
#y = 8 - 5#
#y = 3#

Mar 24, 2018

#(x,y)to(2,3)#

Explanation:

#"we can substitute "x=2" directly into the other equation"#
#"and solve for y"#

#x=2rArry=(4xx2)-5=8-5=3#

#"the point of intersection "=(2,3)#
graph{(y-4x+5)(y-1000x+2000)((x-2)^2+(y-3)^2-0.04)=0 [-10, 10, -5, 5]}