How do you solve $x^{2} - 20 x + 100 = 36$ $x^2 - 20x + 100 = 36$ ?

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Answer 1 · 2018-03-24T17:34:55

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We have, $x^{2} - 20 x + 100 - 36 = 0$ $x^2-20x +100-36=0$

Or, $x^{2} - 20 x + 64 = 0$ $x^2-20x +64=0$

Carrying out middle-term factorization,we get,

$x^{2} - 16 x - 4 x + 64 = 0$ $x^2-16x-4x +64=0$

$x (x - 16) - 4 (x - 16) = 0$ $x(x-16)-4(x-16)=0$

$(x - 16) (x - 4) = 0$ $(x-16)(x-4)=0$

Thus,the two solutions of $x$ $x$ which we get are $x = 16, 4$ $x=16,4$

How do you solve x2−20x+100=36x^2 - 20x + 100 = 36?