How do you evaluate #(- 2\cdot \sqrt { 15} ) ^ { 2}#?

Question

1163 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-25T05:39:50

#60#

#(-2*sqrt15)^2#

Exponentiate #(-2*sqrt15)# to the power of #2# using power of a product rule,

#((-2)^2*(sqrt15)^2)#

Exponentiate inner terms,

#4*15#

Simplify,

#60#

Answer 2 · 2018-03-25T05:42:31

#60# enter image source here

#60#