What does the term "of $1^{\frac{3}{7}}$ $1^(3/7)$ " mean for my answer?

Question

What does the term "of $1^{\frac{3}{7}}$ $1^(3/7)$ " mean for my answer?

Solve: $2^{\frac{1}{3}} + \frac{4}{5}$ $2^(1/3)+4/5$ of $1^{\frac{3}{7}}$ $1^(3/7)$

1 Answer

Impact of this question

1142 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-25T14:38:53

According to law of exponents, $a^{\frac{m}{n}} \Rightarrow \sqrt[n]{a^{m}}$ $a^(m/n) rArr root(n)(a^m)$
But, since $1^{\frac{m}{n}}$ $1^(m/n)$ (or any other power for that matter) $\Rightarrow 1$ $rArr 1$
and "of $x$ $x$ " $\Rightarrow$ $rArr$ part of $x$ $x$
Our question becomes,
$2^{\frac{1}{3}} + \frac{4}{5} \times 1$ $2^(1/3)+4/5 xx 1$
$\sqrt[3]{2} + \frac{4}{5}$ $root(3)2+4/5$

That's it,
Hope this helps :)

Science

Math

Humanities

... and beyond

What does the term "of $1^{\frac{3}{7}}$ $1^(3/7)$ " mean for my answer?

Solve: $2^{\frac{1}{3}} + \frac{4}{5}$ $2^(1/3)+4/5$ of $1^{\frac{3}{7}}$ $1^(3/7)$

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What does the term "of 1371^(3/7)" mean for my answer?

Solve: 213+452^(1/3)+4/5 of 1371^(3/7)

1 Answer

Related questions

Impact of this question

What does the term "of $1^{\frac{3}{7}}$ $1^(3/7)$ " mean for my answer?

Solve: $2^{\frac{1}{3}} + \frac{4}{5}$ $2^(1/3)+4/5$ of $1^{\frac{3}{7}}$ $1^(3/7)$