What does the term "of #1^(3/7)#" mean for my answer?

Solve: #2^(1/3)+4/5# of #1^(3/7)#

1 Answer
Mar 25, 2018

According to law of exponents, #a^(m/n) rArr root(n)(a^m)#
But, since #1^(m/n)# (or any other power for that matter)# rArr 1#
and "of #x#" #rArr# part of #x#
Our question becomes,
#2^(1/3)+4/5 xx 1#
#root(3)2+4/5#

That's it,
Hope this helps :)