How do you evaluate the definite integral int (x-2) dx from [-1,0]?

1 Answer
Mar 25, 2018

-5/2

Explanation:

int_-1^0(x-2)dx

Using the power formula for integral computation, increase the exponent on the variable and divide each term by its new exponent.

[x^2/2-(2x^1)/1]_-1^0

[x^2/2-2x]_-1^0

Now plug in the upper and lower bounds of integration as values for x and subtract.

[((0)^2/2-2(0))-((-1)^2/2-2(-1))]

[(0-0)-(1/2+2)]=-5/2