Question

What are the intercepts for `2x-y=1`?

Answer 1

(0.5, 0) and (0, -1)
graph{2x-y=1 [-10, 10, -5, 5]}

Explanation:

I would always recommend sketching the graph yourelf if you can.

If you can't plot the graph yourself, substitute `x=0` and `y=0` into your equation to find the value of the other variable at that point.
(because graph intercepts `y`-axis when `x=0` and `x`-axis when `y=0`).

At `y=0`, `2x-0=1`, which rearranges to `x=0.5`, by dividing both sides by 2. Hence intercept 1 is (0.5, 0)

At `x=0`, `2(0)-y=1`, which rearranges to `y=-1` by multiplying both sides by -1. Hence, intercept 2 is (0, -1)

Hope this helps!

Answer 2

`"x-intercept "=1/2," y-intercept "=-1`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr0-y=1rArry=-1larrcolor(red)"y-intercept"`

`y=0rArr2x-0=1rArrx=1/2larrcolor(red)"x-intercept"`
graph{(y-2x+1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y+1)^2-0.04)=0 [-10, 10, -5, 5]}