How do you solve $3x + \frac { 1} { 2} = \frac { 2} { 3} x - 6$ ?

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Answer 1 · 2018-03-25T19:45:12

$x=-39/14$

$3x+1/2=2/3x-6$

$3x-2/3x=-1/2-6$

$(3(3)-2)/3x=(2-2(12))/2$ $lArr$ finding the LCD

$7/3x=-13/2$ $lArr$ bring the $7/3$ to the other side to isolate for $x$

$x=-13/2-:7/3$

$x=-13/2*3/7$

$x=-39/14$

How do you solve 3x + \frac { 1} { 2} = \frac { 2} { 3} x - 63x + \frac { 1} { 2} = \frac { 2} { 3} x - 6?