How do you solve for #B# in #A=3(B+C)#?

1 Answer
Mar 25, 2018

B= #A/3-C=B#

Explanation:

#A/3=B+C# then #A/3 -C=B#
In the first step you have to divide both sides by 3 so that removes it on the RHS.
In step two minus the c by both sides and this removes it from the RHS leaving you with the answer.