How do you solve #(x-1)/(x+1)-(2x)/(x-1)=-1#?

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Answer 1 · 2018-03-25T23:05:09

Rationalise your equation by making both fractions have the same denominator.

# (x-1)/(x+1) - (2x)/(x-1) = -1 #

# ((x-1)color (red)((x-1)))/((x+1)color (red)((x-1))) - ((2x)color (red)((x+1)))/((x-1)color (red)((x+1))) = -1 #

# ((x^2-2x+1)-(2x^2+2x))/(x^2-1) = -1 |*(x^2-1) #

# -x^2-4x+1 = 1-x^2 |+x^2-1 #

# 4x=0 |:4 #

# :. x=0 #