What is $2 \sqrt{12} - 3 \sqrt{18}$ $2\sqrt{12} - 3\sqrt{18}$ ?

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Answer 1 · 2018-03-26T06:04:48

$= 4 \sqrt{3} - 9 \sqrt{2}$ $=4sqrt3-9sqrt2$

$2 \sqrt{12} - 3 \sqrt{18}$ $2sqrt12-3sqrt18$

$= 2 \cdot 2 \sqrt{3} - 3 \cdot 3 \sqrt{2}$ $=2*2sqrt3-3*3sqrt2$ $\Leftarrow$ $lArr$ simplified the radicals

$= 4 \sqrt{3} - 9 \sqrt{2}$ $=4sqrt3-9sqrt2$

What is 2√12−3√182\sqrt{12} - 3\sqrt{18}?