Can you find the value of k?

When 2x^4-kx^3+3x^2-x2x4kx3+3x2x is divisible by x-3x3

1 Answer
Mar 26, 2018

color(magenta)(k=186/27 or k=6.8888...

Explanation:

Since x-3 is a factor of 2x^4−kx^3+3x^2−x when you plug in x=3

2(3)^4−k(3)^3+3(3)^2−(3)=0

2(81)-k(27)+3(9)-3=0

162+27-3=27k

27k=186

k=186/27

color(magenta)(k=186/27 or k=6.8888...

~Hope this helps! :)