What is the distance between $(- 4, - 11)$ $(-4,-11)$ and $(13, - 41)$ $(13,-41)$ ?

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Answer 1 · 2018-03-26T11:08:36

Distance $=34.482...$

Apply Pythagorean theorem, where $d$ is the distance between the two points.

$d=sqrt((13--4)^2+(-41--11)^2)$
$color(white)(d)=sqrt((17)^2+(-30)^2)$
$color(white)(d)=sqrt(1189)$
$color(white)(d)=34.482...$

Answer 2 · 2018-03-26T11:11:38

$D=sqrt((y_2-y_1)^2+(x_2-x_1)^2$

subbing in

$D=sqrt((-41-(-11))^2+(13-(-4))^2)$
$D=sqrt(900+289)$
$D=sqrt(1189) units$

Answer 3 · 2018-03-26T11:14:16

$d = sqrt 1189$

distance between $A(x_1, y_1) and (x_2, y_2)$ :

$d = sqrt((x_1-x_2)^2 + (y_1-y_2)^2) = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)$

in this case : $d = sqrt((-4 - 13)^2 + (-11-(-41))^2)$

$d = sqrt (289 + 900) = sqrt 1189$

What is the distance between (-4,-11)(−4,−11)(-4,-11) and (13,-41)(13,−41)(13,-41)?