How do you use the distributive property to simplify #4(2a -3b) #?

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Answer 1 · 2018-03-27T09:48:27

# 8a - 12b#

#color(red)4(color(blue)(2a) - color(green)(3b))#

#= color(red)4 xx (color(blue)(2a) - color(green)(3b))#

#= color(red)4 xx color(blue)(2a) - color(red)4 xx color(green)(3b) #

#=8a - 12b#

Answer 2 · 2018-03-27T10:28:21

#8a-12b#

#"multiply each term in the parenthesis by the 4"#

#rArrcolor(red)(4)(2a-3b)#

#=(color(red)(4)xx2a)+(color(red)(4)xx-3b)#

#=8a+(-12b)=8a-12b#