How do you evaluate 7d – 5c if d = 7 and c = 3?

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Answer 1 · 2018-03-27T13:00:42

#34#

Given: #7d-5c#

Plug in #d=7,c=3#, we get,

#7*7-5*3#

#=49-15#

#=34#

Answer 2 · 2018-03-27T13:04:16

49-15=34

First begin by substituting each variable for the number amount that is given (7 in for d and 3 for c). It will end up looking something like this:

#7(7)-5(3) or (7*7)-(5*3)#

It's just simple multiplication and subtraction from here on out:

#7*7=49 and -5*3=15#

So all simplified we get:

#49-15=34#