How do you solve the system of equations $9 x + 3 y = - 18$ $9x + 3y = - 18$ and $3 x - 5 y = - 24$ $3x - 5y = - 24$ ?

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Answer 1 · 2018-03-27T19:08:06

x=-3
y=3

= $9 x + 3 y = - 18$ $9x+3y=-18$
Divide 3 on both sides

= $3 x + y = - 6$ $3x+y=-6$

Now Subtracting

= $(3 x + y = - 6) - (3 x - 5 y = - 24)$ $(3x+y=-6)-(3x-5y=-24)$

= $6 y = 18$ $6y=18$

** = $y = 3$ $y=3$ **

For $x$ $x$ doing putting in following

= $3 x - 5 y = - 24$ $3x-5y=-24$

= $3 x - 5 (3) = - 24$ $3x-5(3)=-24$

= $3 x = - 9$ $3x=-9$

** = $x = - 3$ $x=-3$ **

How do you solve the system of equations 9x+3y=−189x + 3y = - 18 and 3x−5y=−243x - 5y = - 24?