How do you simplify $\frac{3 x^{6} y \cdot 4 x^{2} y}{38 x^{9} y^{- 2}}$ $\frac { 3x ^ { 6} y \cdot 4x ^ { 2} y } { 38x ^ { 9} y ^ { - 2} }$ ?

Question

1149 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-27T19:22:00

Simplify

= $\frac{12 x^{8} y^{4}}{38 x^{9}}$ $(12x^8y^4)/(38x^9$

= $12 \frac{y^{4}}{38 x}$ $12y^4/(38x$

= $6 \frac{y^{4}}{19 x}$ $6y^4/(19x)$

How do you simplify \frac { 3x ^ { 6} y \cdot 4x ^ { 2} y } { 38x ^ { 9} y ^ { - 2} }3x6y⋅4x2y38x9y−2\frac { 3x ^ { 6} y \cdot 4x ^ { 2} y } { 38x ^ { 9} y ^ { - 2} }?