Question

How do you solve `3x^2 - 2x - 2 = 0` using the quadratic formula?

Answer 1

Apply the formula:
`x_1=(-b+(b^2-4*a*c)^(1/2))/(2*a)`
`x_2=(-b-(b^2-4*a*c)^(1/2))/(2*a)`

Explanation:

`x_1=(-(-2)+((-2)^2-4*3*(-2))^(1/2))/(2*3)=(1+√7)/3`
`x_1=(-(-2)-((-2)^2-4*3*(-2))^(1/2))/(2*3)=(1-√7)/3`