How do you use the laws of exponents to simplify the expression # ((3^2)/(3^-3))^(3/5)#?

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Answer 1 · 2018-03-28T15:45:28

It simplifies to #27#.

#(\frac{3^2}{3^{-3}})^{\frac{3}{5}}=(3^{(2+3)})^{\frac{3}{5}}=(3^5)^{\frac{3}{5}}=3^{5\cdot \frac{3}{5}}=3^3=27#

Answer 2 · 2018-03-28T15:46:41

#3^3#. See below

You have several ways to resolve. This could be the simpliest...

First operate whithin the braquets using laws of exponents

#3^2/3^(-3)=3^(2-(-3))=3^5#

Now, apply exponent #3/5# to this result

#(3^5)^(3/5)=3^(5·3/5)=3^3#