How do you solve #\frac{x + 2}{4} = - 2#?

Question

1231 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-28T16:33:29

#x=-10#

Given -

#(x+2)/4=-2#

#(x+2)/4 xx 4=-2 xx 4#

#(x+2)/cancel4 xx cancel4=-8#

#x+2=-8#

#x+2-2=-8-2#

#xcancel(+2)cancel(-2)=-10#

#x=-10#

Answer 2 · 2018-03-28T16:34:25

#x=-10#

Multiply both sides by #4#.

Then you should get #[(x+2)/4]*4=-2*4#

Multiply to get #x+2=-8#

Subtract #2# from both sides to isolate #x#.

#x+2-2=-8-2#

#x=-10#

Yay!