How do you simplify #m^4 div m #?

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Answer 1 · 2018-03-28T17:47:34

#m^3#

#(m^4)/m#

#(m*m*m*m)/m# (One m on the top and one m on the bottom cancel each other out)

#m*m*m# = #m^3#

Answer 2 · 2018-03-28T17:52:14

Rebember: #1/a=a^(-1)#

#m^4/m=m^(4-1)=m^3#
For more: Exponentiation (see section: Integer exponents, Identities and properties)