How do you multiply $(4x-2)(4x+2)$ ?

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Answer 1 · 2018-03-28T17:58:10

Multiply each factor with each factor.

$(4x-2)(4x+2)=4x*4x+4x*2-2*4x-2*2=$
$=4^2x^2+(8-8)x-4=16x^2-4$

You can remember this formula:
$(a+b)(a-b)=a^2-b^2$

$(a-b)(a+b)=a*a+a*b-b*a-b*b=$
$=a^2+(ab-ba)-b^2=a^2-b^2$

How do you multiply (4x-2)(4x+2)(4x-2)(4x+2)?