Question

What is the standard form of `y= (-x+1)^3-(-3x+1)^2`?

Answer 1

`y=-28x^3+30x^2-12x+2`

Explanation:

`y=(-x+1)^3-(-3x+1)^2`

`y=(1-x)^3+(1-3x)^2`

`y=1^3-3xx1^2 xxx+3xx1xxx^2-x^3+1^3-3xx1^2xx3x+3xx1xx(3x)^2-(3x)^3`

`y=1-3x+3x^2-x^3+1-9x+27x^2-27x^3`

`y=-x^3-27x^3+3x^2+27x^2-9x-3x+1+1`

`y=-28x^3+30x^2-12x+2`