How do you find the sum of the infinite geometric series given $a_1=36$ and r=2/3?

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Answer 1 · 2018-03-29T03:17:52

it is 108

the infinte geometric series sum is given as
$a_1/(1-r)$
so the infinite sum of given series is
$36/(1-2/3) =36/(1/3) =36*3=108$

How do you find the sum of the infinite geometric series given a_1=36a_1=36 and r=2/3?