How do you find the sum of the infinite geometric series given $a_{1} = 36$ $a_1=36$ and r=2/3?

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How do you find the sum of the infinite geometric series given $a_{1} = 36$ $a_1=36$ and r=2/3?

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Answer 1 · 2018-03-29T03:17:52

it is 108

Explanation:

the infinte geometric series sum is given as
$\frac{a_{1}}{1 - r}$ $a_1/(1-r)$
so the infinite sum of given series is
$\frac{36}{1 - \frac{2}{3}} = \frac{36}{\frac{1}{3}} = 36 \cdot 3 = 108$ $36/(1-2/3) =36/(1/3) =36*3=108$

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How do you find the sum of the infinite geometric series given $a_{1} = 36$ $a_1=36$ and r=2/3?

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Science

Math

Humanities

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How do you find the sum of the infinite geometric series given a1=36a_1=36 and r=2/3?

1 Answer

Explanation:

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How do you find the sum of the infinite geometric series given $a_{1} = 36$ $a_1=36$ and r=2/3?