How do you solve the following system: $x-3y=20 , 7x+15y=32$ ?

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Answer 1 · 2018-03-29T12:26:17

$x=11$
$y=-3$

= $x-3y=20$

= $x=20+3y$ **

Put above in other equation

= $7(20+3y)+15y=32$

= $140+21y+15y=32$

= $21y+15y=32-140$

= $36y=-108$

= $y=-3$

Now for $x$

= $x-3(-3)=20$

= $x+9=20$

= $x=11$

Hope this helps!

How do you solve the following system: x-3y=20 , 7x+15y=32 x-3y=20 , 7x+15y=32 ?