How do you multiply #(9k+q)(2k-q)#?
3 Answers
Mar 29, 2018
Explanation:
To multiply two polynomials, simply multiply each term in the first parenthesis with each term in the second, and sum everything.
So, we have:
- First element of first parenthesis times first element of second parenthesis:
#9k * 2k = 18k^2# - Second element of first parenthesis times first element of second parenthesis:
#q * 2k = 2kq# - First element of first parenthesis times second element of second parenthesis:
#9k * -q = -9kq# - Second element of first parenthesis times second element of second parenthesis:
#q * (-q) = -q^2#
Summing it up:
Mar 29, 2018
Use FOIL methos (First,Outer,Inner,Last)
Explanation:
(9k+q)(2k-q)
(9k2k) + (9k-q2k) + (q-q)
=
Hope this helps!
Mar 29, 2018
Explanation:
(9k+q)(2k-q)
=)
=)