How do you solve the system of equations 4y=2x−9 and −6x−3y=3?

1 Answer
AltairSafir
Mar 30, 2018

The system is:
4y=2x−9
−6x−3y=3

Explanation:

Expand the first equation by 3.
6x−27=12y
−6x−3y=3
sum the equations:
0−27−3y=12y+3
rearrange it:
−3y−12y=3+27
−15y=30
y=−2
put it in one of the equation:
4⋅(−2)=2x−9
2x=−8+9=1
x=12

Related questions
Impact of this question
1205 views around the world
You can reuse this answer
Creative Commons License