How do you find the domain of f(x)= (8x)/((x-1)(x-2)) f(x)=8x(x1)(x2)?

2 Answers
Mar 30, 2018

x inRR,x!=1,2

Explanation:

f(x)" is defined for all values of x except values which"
"make f(x) undefined"

"the denominator of f(x) cannot be zero as this would make"
"f(x) undefined. Equating the denominator to zero and "
"solving gives the values that x cannot be"

"solve "(x-1)(x-2)=0

rArrx=1,x=2larrcolor(red)"are excluded values"

"domain is "x inRR,x!=1,2

(-oo,1)uu(2,+oo)larrcolor(blue)"in interval notation"
graph{(8x)/((x-1)(x-2)) [-10, 10, -5, 5]}

Mar 30, 2018

Ask yourself where the function is defined.

Explanation:

Since the given function is a rational function, look where is the denominator is equal to zero. ((8x)/0 is not defined)
(x-1)(x-2)=0 if x_1=1 or x_2=2
The domain of f(x) is : RR-{1,2} real number except 1 and 2