Question

How do you solve `\frac { 5x - 3} { 4} = 7`?

Answer 1

`x=31/5`

Explanation:

`(5x-3)/4=7`

Cross multiply

`5x - 3= 7 xx 4`

`5x - 3= 28`

Then add `33` on both sides

`5x - 3 + 3 = 28 + 3`

`5x = 31`

`x = 31/5`

Answer 2

`x=31/5`

Explanation:

`"to eliminate the fraction multiply both sides by 4"`

`cancel(4)^1xx(5x-3)/cancel(4)^1=4xx7`

`rArr5x-3=28`

`"add 3 to both sides"`

`5xcancel(-3)cancel(+3)=28+3`

`rArr5x=31`

`"divide both sides by 5"`

`(cancel(5) x)/cancel(5)=31/5`

`rArrx=31/5`

Answer 3

`x=31/5`

Explanation:

To get rid of the `4` in the denominator, we can multiply both sides by `4` to get

`5x-3=28`

Next, add `3` to both sides to get

`5x=31`

Lastly, we can divide both sides by `5` to get

`x=31/5`

Hope this helps!