How to do 189th question?

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How to do 189th question?

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Answer 1 · 2018-03-30T18:44:24

(2)

Explanation:

A force

$P = (0, 0, - m g)$ $P = (0,0,-m g)$

shall be decomposed as the sum

$P = F_{1} + F_{2} + F_{3}$ $P = F_1+F_2+F_3$ with

$F_{1} = f ({cos 30}^{\circ}, {sin 30}^{\circ}, {sin 30}^{\circ})$ $F_1 = f(cos30^@,sin30^@,sin30^@)$
$F_{2} = f (- {cos 30}^{\circ}, {sin 30}^{\circ}, {sin 30}^{\circ})$ $F_2 = f(-cos30^@,sin30^@,sin30^@)$
$F_{3} = f (0, - 1, {sin 30}^{\circ})$ $F_3 = f(0,-1,sin30^@)$

then with the third component

$- m g = 3 f {sin 30}^{\circ}$ $-mg = 3fsin 30^@$ hence

$| f | = \frac{m g}{3 {sin 30}^{\circ}} = \frac{2}{3} m g$ $absf = (mg)/(3sin30^@) = 2/3mg$

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How to do 189th question?

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